Chem
posted by Cairy .
A 10.0% by mass H2SO4(aq) solution has a density of 1.07 g·cm3.
How many milliliters of solution contain 8.34 g of H2SO4?
What mass (in grams) of H2SO4 is in 248 mL of solution?
It's been a while since I have had a chem class...so sorry if this seems really easy I just don't understand how to find it...

Okay... I think this might help... but I'm really not sure either.
density=mass/volume
cm3=mL
1.volume=mass/density=8.34g/(1.07g/mL)=7.79mL
2.mass=density*volume=1.07*248=265.36g.
Here's where I'm confused. Do we have to multiply these two answers by .1 because it's 10% H2SO4 by mass? If that's the case, you can probably take it from here. Hope this helps. Good luck. 
I finally figured it out actually. And yes the .1 has to be multiplied in there. answers end up being 77.93 mL and 26.54g

77.93 is not right.
Annon had it right.
mass = volume x density
8.34g = volume x 1.07 g/mL
volume = 8.34/1.07 = 7.79 mL. 
CV
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