Determine the mole fraction of acetone in a solution prepared by adding 0.456 kg of (CH3)2CO to 0.899 L of C4H8O.
Molar Mass (g/mol)
(CH3)2CO 58.05
C4H8O 72.12
Density (g/ml):
(CH3)2CO 0.7899
C4H8O 0.8892
Name/Formula:
acetone
(CH3)2CO
tetrahydrofuran
C4H8O
I need help!!
moles fraction acetone = moles aetone/(moles acetone + moles THF).
Convert g acetone to moles.
Convert L THF to grams and to moles.
Substitute into the above mole fraction formula.
figure the moles of acetone by 256/58.05
next, figure the moles of Ch4H8O
mass= 899ml*.8992g/ml
moles= mass/mole mass
Mole fraction acetone = molesacetone/total moles
To determine the mole fraction of acetone in the solution, you first need to calculate the number of moles of acetone and tetrahydrofuran in the solution.
Step 1: Calculate the moles of acetone (CH3)2CO:
Given mass of acetone = 0.456 kg
Molar mass of acetone (CH3)2CO = 58.05 g/mol
First, convert the mass of acetone from kg to g:
0.456 kg * 1000 g/kg = 456 g
Next, calculate the moles of acetone:
moles of acetone = mass of acetone / molar mass of acetone
moles of acetone = 456 g / 58.05 g/mol ≈ 7.864 mol
Step 2: Calculate the moles of tetrahydrofuran C4H8O:
Given volume of tetrahydrofuran = 0.899 L
Density of tetrahydrofuran C4H8O = 0.8892 g/ml
Molar mass of tetrahydrofuran C4H8O = 72.12 g/mol
First, calculate the mass of tetrahydrofuran:
mass of tetrahydrofuran = volume of tetrahydrofuran * density of tetrahydrofuran
mass of tetrahydrofuran = 0.899 L * 0.8892 g/ml ≈ 0.7987 g
Next, calculate the moles of tetrahydrofuran:
moles of tetrahydrofuran = mass of tetrahydrofuran / molar mass of tetrahydrofuran
moles of tetrahydrofuran = 0.7987 g / 72.12 g/mol ≈ 0.0111 mol
Finally, calculate the mole fraction of acetone:
mole fraction of acetone = moles of acetone / (moles of acetone + moles of tetrahydrofuran)
mole fraction of acetone = 7.864 mol / (7.864 mol + 0.0111 mol) ≈ 0.9986
The mole fraction of acetone in the solution is approximately 0.9986.