Algebra II

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V(X)=x^3-5x^2-8x+12
the depth is x+2
Find linear expressions with integer coefficients for the other dimensions and next if the depth of the chest is 9feet deep what are the other dimensions?

  • Algebra II -

    V = depth * width * length
    V = (x+2) * w * l = x^3 - 5x^2 -8x +12
    so divide x^3 - 5x^2 -8x +12 by (x+2)
    and get
    l * b = x^2 -7x +6
    which is
    (x-6)(x-1)
    so
    length = x-1
    width = x-6
    depth = x+2
    take it from there

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