# pseudocode programming

posted by .

Develop an algorithm or write pseudocode to determine if a citizen is eligible to vote. The
criteria for eligibility are that the citizen must be 18 or older and must not be a convicted
felon. The algorithm must continuously accept as input only the names, year of birth and
felony status of a citizen. The algorithm should continue to accept this information until a
year of 0 (zero) is input.
Print the name of the citizen and a statement saying whether or not the citizen is eligible to
vote.

• pseudocode programming -

I'm sorry I can't help you with the pseudocode, but in many states convicted felons can vote if they've already served their prison sentence.

• pseudocode programming -

ok thank you.

• pseudocode programming -

if i develop one can you be able to look it over?

• pseudocode programming -

I'm computer illiterate. <g>

But after you develop a code, post it along with your instructions as a new question. Someone may be able to help you then.

• pseudocode programming -

lol ok then thnks.

• pseudocode programming -

Develop an algorithm or write pseudocode to determine if a citizen is eligible to vote. The
criteria for eligibility are that the citizen must be 18 or older and must not be a convicted
felon. The algorithm must continuously accept as input only the names, year of birth and
felony status of a citizen. The algorithm should continue to accept this information until a
year of 0 (zero) is input.

THIS IS THE CODE.

GET name
GET yob
GET status
age = 2010 - yob
status = "felon" THEN
WRITE age <= "18" THEN
Felonystatus = "is a felon"
ELSE
Felonystatus = "not a felon"

PRINT name, yob, felonystatus

• pseudocode programming -

You code doesn't loop, so only 12 name can be input.

DO WHILE .T.
GET name
GET yob
IF yob = 0 THEN
EXIT DO
ENDIF
GET status
age = YEAR() - yob
IF age >= 18 AND status != "FELON"
PRINT name + " is elligible to vote"
ELSE
PRINT name + " is not elligible to vote."
ENDIF
ENDDO

• pseudocode programming -

I don't understan what you saying.

• pseudocode programming -

And that code does'nt compile.

• Computer -

START
If 'psuedocode' = hard
Stop
ENDIF

• pseudocode programming -

Start
Input age;
if age >= 18
Print Eligible;
Else
Print Not Eligible;
Stop

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