posted by Stuck .
"Find the total energy lost by the contents of a Styrofoam picnic cooler when a 3.60 kg block of ice placed inside the cooler completely melts (at 0 Celsius). The ice had an initial temperature of -10.00 Celsius." (Answer is 1.27*10^3 kJ).
I was thinking of using q=mct, but I didn't get the answer. I might have done something wrong though...
The ice loses heat in moving from a temperature of -10.00 C to O C. For that you use q = mc*delta T. Remember to use the specific heat of ICE (not water) for c in the equation. Then the ice melts and that is mass ice x heat fusion. Add the two qs together. That should do it.