8th grade algebra
posted by val .
the length of a rectangular garden is 5 feet longer than its width. The garden is surrounded by a 2-foot-wide-sidewalk. The sidewalk has an area of 76 square feet. Find the dimensions of the garden
Let the width of the garden be x ft
then the length is x+5 ft.
area = x(x+5)
width of garden with sidewalk = x+4
length of garden with sidewalk = x+9
(x+4)(x+9) - x(x+5) = 76
solve, the x^2 will drop out
X^2 will drop and we will combine the like terms(13x and -5x) and 36 will go to the other side
L=10ft since L=x+5
Area of living room with length being X+5 and width being 20