8th grade algebra
posted by val .
the length of a rectangular garden is 5 feet longer than its width. The garden is surrounded by a 2footwidesidewalk. The sidewalk has an area of 76 square feet. Find the dimensions of the garden

Let the width of the garden be x ft
then the length is x+5 ft.
area = x(x+5)
width of garden with sidewalk = x+4
length of garden with sidewalk = x+9
(x+4)(x+9)  x(x+5) = 76
solve, the x^2 will drop out 
(X+4)(x+9)x(x+5)=76
(x^2+9x+4x+36)x(x+5)=76
x^2+13x+36x^25x=76
X^2 will drop and we will combine the like terms(13x and 5x) and 36 will go to the other side
8x=7636
8x=40
x=5
W=5ft
L=10ft since L=x+5 
Area of living room with length being X+5 and width being 20
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