8th grade algebra

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the length of a rectangular garden is 5 feet longer than its width. The garden is surrounded by a 2-foot-wide-sidewalk. The sidewalk has an area of 76 square feet. Find the dimensions of the garden

  • 8th grade algebra -

    Let the width of the garden be x ft
    then the length is x+5 ft.

    area = x(x+5)

    width of garden with sidewalk = x+4
    length of garden with sidewalk = x+9

    (x+4)(x+9) - x(x+5) = 76
    solve, the x^2 will drop out

  • 8th grade algebra -

    (X+4)(x+9)-x(x+5)=76
    (x^2+9x+4x+36)-x(x+5)=76
    x^2+13x+36-x^2-5x=76
    X^2 will drop and we will combine the like terms(13x and -5x) and 36 will go to the other side
    8x=76-36
    8x=40
    x=5

    W=5ft
    L=10ft since L=x+5

  • 8th grade algebra -

    Area of living room with length being X+5 and width being 20

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