Math
posted by Anonymous .
Transform to a Cartesian Equation:
a. x = sin t
y = cos t
b. x = t^(1/3) 1
y = t^2  t

This is what I have for B so far:
y = t(t1)
t = (x+1)^3
y = (x+1)^3[(x+1)^31]
= (x^3 + 3x^2 + 3x + 1)[x^3+3x^2+3x]
...???
and IDK about A.
Help?
Thank you so much!

Math 
drwls
A: x^2 + y^2 = 1
This plots as a circle around the origin with radius = 1.
Respond to this Question
Similar Questions

trig
Reduce the following to the sine or cosine of one angle: (i) sin145*cos75  cos145*sin75 (ii) cos35*cos15  sin35*sin15 Use the formulae: sin(a+b)= sin(a) cos(b) + cos(a)sin(b) and cos(a+b)= cos(a)cos(b)  sin(a)sin)(b) (1)The quantity … 
tigonometry
expres the following as sums and differences of sines or cosines cos8t * sin2t sin(a+b) = sin(a)cos(b) + cos(a)sin(b) replacing by by b and using that cos(b)= cos(b) sin(b)= sin(b) gives: sin(ab) = sin(a)cos(b)  cos(a)sin(b) … 
algebra
Can someone please help me do this problem? 
math
Eliminate the parameter (What does that mean? 
Mathematics  Trigonometric Identities
Let y represent theta Prove: 1 + 1/tan^2y = 1/sin^2y My Answer: LS: = 1 + 1/tan^2y = (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y) = (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y) = (sin^2y … 
TRIG!
Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1  (3/4)sin^2 2x work on one side only! Responses Trig please help!  Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x + cos^6 … 
Math
Solve this equation algebraically: (1sin x)/cos x = cos x/(1+sin x)  I know the answer is an identity, and when graphed, it looks like cot x. I just don't know how to get there. I tried multiplying each side by its conjugate, but … 
calculus
PLEASE HELP! Transform polar equation to an equation in Cartesian (rectangular) coordinates. Then identify where it locate on the graph. r sin θ = 4 
calculus
PLEASE HELP! Transform polar equation to an equation in Cartesian (rectangular) coordinates. Then identify where it locate on the graph. r sin θ = 4 
Math
Show that for real x that {[cos x + 2 sin x + 1]/[cos x + sin x] } cannot have a value between 1 and 2. Let y = [(cos x+2 sin x + 1)/(cos x + sin x) ] y(cos x + sin x) = (cos x + 2 sin x + 1) sin x(y2) + cos x(y1)=1 , I just feel …