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PHYS 1112

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A defibrillator is used during a heart attack to restore the heart to its normal beating pattern. A defibrillator passes 18 A of current
through the torso of a person in 2.0 ms.

a) How much charge moves during this time?

b) How
many electrons pass through the wires connected to the patient?

  • PHYS 1112 -

    Q = I*t, which means
    (charge,coulombs)
    = [current,amps)*(time,seconds)

    Divide the Charge Q by the electron charge, e, to get the number of electrons.

    Look up the electron charge if you don't know it. It is a number you should memorize. You should also memorize the formula.

  • PHYS 1112 -

    122

  • PHYS 1112 -

    a) 0.036 C

    b) 2.25E17

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