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Benzene has a heat of vaporization of 30.72 kj/mol and a normal boiling point of 80.1 degrees celcius.

At what temperature does Benzene boil when the external pressure is 440 torr?

Since...I didn't get the right answer. I'll just show my work and see if anyone can help me. Answer has to be in 2 sig figs.

Ln (440/760) = -30720/8.3145 * (1/x - 1/353.25)

I got x = 335.58. Since I was using Kelvin, the celcius is 63 degrees...something is off. What should I be getting?

  • Chem. -

    Try removing the negative sign for delta Hvap and get back to us.

  • Chem. -

    nevermind i had it right the whole time. thank you

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