Chemistry HELP ME!!!!

posted by .

A sloution of calcium nitrate, C(NO3), reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(ag). When 45.00 mL of 4.8724 x 10 -1M Ca(NO3)2 solution was added to 60.00 mL of 9.9981 x 10 -1M NH4F solution, 1.524g of CaF2 was isolated.

(1) Write the equation for the reaction, showing the staes of substances.

(2) Calculate the number of moles of Ca(NO3)2 orginally present.

(3) calculate the number of moles of NH4F present

(4) Identify the limiting reagent.

(5) Calculate the theoretical yeild, in grams, of CaF2.

(6) Calculate the percent yield of CaF2.

  • Chemistry HELP ME!!!! -

    Ca(NO3)2(aq) + 2NH4F(aq) ==> CaF2(s) + 2NH4NO3(aq)

    2. moles = M x L
    3. moles = M x L
    4. Using the coefficients in the balanced equation, convert mole of Ca(NO3)2 to moles CaF2. With the same procedure, convert moles NH4F to moles CaF2. The smaller number of moles will be the correct # moles for CaF2 and the reactant that produced that number will be the limiting reagent.
    5. The theoretical yield will be obtained by using the smaller number of moles CaF2 and that times molar mass CaF2.
    6. percent yield = (actual yield/theoretical yield)*100 = ??
    theoretical yield you obtained in 5. Actual yield is given in the problem as 1.524 g CaF2.
    Post your work if you get stuck.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    if you added sulfuric acid to calcium nitrate what products in addition to calcium sulphate would you get if any ?
  2. Chemistry

    Calcium nitrate and ammoonium fluoride react to form calcium fluoride, dinitrogenmonoxide and water vapor. What mass of each substance is present after 28.42 g of calcium nitrate and 29.60 g of ammonium fluoride react completely?
  3. Chemistry 120

    A sloution of calcium nitrate, C(NO3), reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(ag). When 45.00 mL of 4.8724 x 10 -1M Ca(NO3)2 solution was added to 60.00 …
  4. DrBob222-Questions

    Can you please check these for me. Thank you very much in return:-) For Al2(SO4)3 you gave me Aluminum ion and Sulfate ion. These are the rest: CaCl2 = Calcium ion and Chlorite ion Na2O = Sodium ion and Oxygen ion AgCl = silver ion …
  5. chemistry

    When a 3.90-g sample of solid ammonium nitrate dissolves in 60.0 g of water in a coffee-cup calorimeter, the temperature drops from 24.5°C to 19.3°C. Calculate DH (in kJ/mol NH4NO3) for the solution process NH4NO3(s) ---> NH4+(aq) …
  6. Chemistry

    A solution of calcium nitrate, Ca(NO3)2, reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(aq). When 45.00 mL of 4.8724 x 10-1 M Ca(NO3)2 solution was added to 60.00 …
  7. Chemistry

    A solution of calcium nitrate, Ca(NO3)2, reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(aq). When 45.00 mL of 4.8724 x 10-1 M Ca(NO3)2 solution was added to 60.00 …
  8. Chemistry

    A solution of calcium nitrate, Ca(NO3)2, reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(aq). When 45.00 mL of 4.8724 x 10-1 M Ca(NO3)2 solution was added to 60.00 …
  9. Chemistry

    A solution of calcium nitrate, Ca(NO3)2, reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(aq). When 45.00 mL of 4.8724 x 10-1 M Ca(NO3)2 solution was added to 60.00 …
  10. Chemistry

    A sample of calcium fluoride with a mass of 15.0 g contains 8.40 g of calcium. Assuming that the sample is pure calcium fluoride, how much calcium would be present in a 30.0 g sample?

More Similar Questions