hello i just want a answer in these question:

please. im begging!

I. Use Newton’s method to approximate the real root to 4 decimal places.

1. X^3-3X+1=0

2 . X^3-X-2=0

3. 2X-3SINX=0

Well, this is simple, you just have to form the derivative of the presumed functions.

e.g. d/dx[2x-3sinx]=:g(x); [2x-3sinx]=:f(x)

Afterwards, you have to numericaly take the following algorithm as many times as necessary in order to be yielded the wanted result:

x_(n+1)= x_n-f(x_n)/g(x_n)

Bear in mind that this is an iteration, i.e. of repeated application of this algorithms comes to a number whose 4th decimal has not changed concerning the preceding one, you'll be done.

hello dongo. First of all thank you but I'm sorry I can't understand it because the question is from my older sister who has a Flu right now and she ask me to post it on the internet so somebody can answer it. Can you solve it for her? please? She will be very very thankful to you.

There's absolutely no use in doing so. Even though she's ill, I am really convinced about her managing to solve this, supplied with the correct algorithms. (In fact, I do ot understand why it is always about calculating. Proving the applicability of this algorithm would be way better... She can greet her profesor from me...)

she said thanks. i just want to help her. btw thank you very much!

Find the limit. If the limit doesn't exist, explain why. lim x approaches 5 x^2-3x-10/x^2-10x+25

Hello! I can help you with that. To approximate the real roots using Newton's method, you'll need to follow these steps:

1. Start by rearranging the equation to the form f(x) = 0.

2. Compute the derivative of the function f(x), which will be used in the Newton's method formula.

3. Choose an initial guess, x0, which is typically a reasonable estimate of the real root.

4. Use the Newton's method formula:

x1 = x0 - f(x0)/f'(x0)

Keep applying this formula iteratively until the desired level of accuracy is achieved. The new value obtained, x1, becomes the new x0 for the next iteration.

5. Continue iterating until the difference between consecutive approximations is smaller than the desired tolerance (e.g., 0.0001 for 4 decimal places).

Now, let's solve the questions using Newton's method:

I. X^3-3X+1=0:

1. Rearrange the equation: f(x) = x^3 - 3x + 1 = 0

2. Calculate the derivative of f(x): f'(x) = 3x^2 - 3

3. Select an initial guess, x0 (e.g., x0 = 1)

4. Use the Newton's method formula to approximate the root:

x1 = x0 - (x0^3 - 3x0 + 1) / (3x0^2 - 3)

Calculate x1 and repeat the process until the desired accuracy is achieved.

II. X^3-X-2=0:

1. Rearrange the equation: f(x) = x^3 - x - 2 = 0

2. Calculate the derivative of f(x): f'(x) = 3x^2 - 1

3. Select an initial guess, x0 (e.g., x0 = 1)

4. Use the Newton's method formula to approximate the root:

x1 = x0 - (x0^3 - x0 - 2) / (3x0^2 - 1)

Calculate x1 and repeat the process until the desired accuracy is achieved.

III. 2X-3SINX=0:

1. Rearrange the equation: f(x) = 2x - 3sin(x) = 0

2. Calculate the derivative of f(x): f'(x) = 2 - 3cos(x)

3. Select an initial guess, x0 (e.g., x0 = 0)

4. Use the Newton's method formula to approximate the root:

x1 = x0 - (2x0 - 3sin(x0)) / (2 - 3cos(x0))

Calculate x1 and repeat the process until the desired accuracy is achieved.

Remember to perform the necessary calculations for each iteration until the desired level of accuracy is reached.