Based on the balanced equation
2I2O5 + 10NO → 5N2O4 + 2I2
calculate the number of excess reagent units remaining when 188 I2O5 molecules and 850 NO molecules react?
do i start with a new balance equation in order to solve it
can anyone help me with this
To determine the number of excess reagent units remaining, you do not need to write a new balanced equation. However, you should first identify the limiting reagent, which is the reactant that is completely consumed in the reaction and determines the maximum amount of product that can be formed.
To find the limiting reagent, you compare the number of moles of each reactant to the stoichiometric ratio given in the balanced equation. Here are the steps to follow:
1. Convert the given number of molecules of I2O5 and NO to moles. To do this, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol).
2. Use the stoichiometric ratio in the balanced equation to determine how many moles of N2O4 can be formed from each reactant. Since the ratio is 2:5, you divide the number of moles of each reactant by its corresponding stoichiometric coefficient.
3. The smallest value obtained in step 2 represents the limiting reagent. The reactant with the smallest number of moles will be completely consumed, while there will be excess moles of the other reactant.
4. Calculate the number of remaining moles of the excess reagent by subtracting the moles of the limiting reagent used from the initial moles of the excess reagent.
5. Finally, convert the remaining moles of the excess reagent back to the number of molecules by multiplying by Avogadro's number.
By following these steps, you can determine the number of excess reagent units remaining.