write a polynomial that expresses the area of a rectangle whose length is 3 feet more than twice the width
Let x denote the width of the rectangle, measured in ft..
The height h is by virtue of the assignment defined as h(x)= 2*x+3. Again, the measurement's unit is ft..
The area of a rectangle is calculated by:
Area(h, x) = h*x
Substituting h=h(x)=2*x+3, we obtain the final result:
Area(h, x) = (2*x+3)*x = 2*x²+3x. This is measured in square-ft.
THANKS DONGO!!
To write a polynomial expression for the area of a rectangle, we need to express the length and width of the rectangle in terms of a variable, such as 'x'.
Let's let 'x' represent the width of the rectangle.
According to the given information, the length is 3 feet more than twice the width.
Twice the width would be 2x, and three feet more than that would be 2x + 3.
Therefore, the length of the rectangle is 2x + 3.
The area of a rectangle is given by the formula: Area = Length * Width.
Substituting the values we have:
Area = (2x + 3) * x
Expanding the expression:
Area = 2x^2 + 3x
So, the polynomial expression that represents the area of the rectangle is 2x^2 + 3x.