Suppose the cost C(q) (in dollars) of producing a quantity q of a product

equals

C(q) = 500 + 2q +1/5q^2

The marginal cost M(q) equals the instantaneous rate of change of the
total cost. Find the marginal cost when a quantity of 10 items are being
produced.

To find the marginal cost, we need to take the derivative of the cost function C(q) with respect to q.

C(q) = 500 + 2q + 1/5q^2

Taking the derivative with respect to q:

dC(q)/dq = d(500 + 2q + 1/5q^2)/dq

Using the power rule, we have:

dC(q)/dq = 0 + 2 + (2/5)q

Simplifying, we get:

dC(q)/dq = 2 + (2/5)q

Now we need to evaluate the derivative at q = 10. Plugging in q = 10 into the derivative:

dC(q)/dq = 2 + (2/5)(10)
= 2 + 4
= 6

Therefore, the marginal cost when a quantity of 10 items are being produced is $6.

To find the marginal cost when a quantity of 10 items are being produced, we need to determine the derivative of the cost function C(q) with respect to q.

The cost function is given as C(q) = 500 + 2q + 1/5q^2. Taking the derivative of this function will give us the marginal cost function.

Step 1: Differentiate the constant term
The derivative of a constant term is always zero. In this case, the constant term is 500.

d/dq (500) = 0

Step 2: Differentiate the linear term
The derivative of a linear term is equal to its coefficient. In this case, the linear term is 2q.

d/dq (2q) = 2

Step 3: Differentiate the quadratic term
To differentiate the quadratic term, we use the power rule. The power rule states that the derivative of x^n is nx^(n-1). In this case, the quadratic term is 1/5q^2.

d/dq (1/5q^2) = (1/5) * 2q^(2-1) = (2/5)q

Step 4: Add up the derivatives
Now, we add up the derivatives we obtained in steps 1, 2, and 3 to find the derivative of the cost function.

dC/dq = d/dq (500 + 2q + 1/5q^2) = 0 + 2 + (2/5)q

Simplifying the expression gives us:

dC/dq = 2 + (2/5)q

Step 5: Substitute the quantity q = 10 into the marginal cost function
To find the marginal cost when a quantity of 10 items are being produced, we substitute q = 10 into the derivative function.

M(q) = 2 + (2/5)q

M(10) = 2 + (2/5)(10)
M(10) = 2 + 4
M(10) = 6

Therefore, the marginal cost when a quantity of 10 items are being produced is $6.