# calculus

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can someone show me step by step how to evaluate the integral of 2(sinx)^2 dx

I just don't understand how to do it....

• calculus -

Isn't there are identity

sin2x=1-2sin^2 x ?

• calculus -

I don't understand what you are saying. there is no sin2x in my equation i don't think
i have to evaluate the integral 2(sin^2x)

• calculus -

Try
sin(x)sin(y)=(1/2)(cos(x-y)-cos(x+y))
Put y=x and noting that cos(0)=1, you will have a simpler expression to integrate.

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