Physics

posted by .

The electric field at the point x=5.00 cm and y=0 points in the positive x direction with a magnitude of 10.0 N/C. At the point x=10.0 cm and y=0, the electric field points in the positive x direction with a magnitude of 15.0 N/C. Assuming the field is produced by a single point charge, find (a) it's location and (b) the sign and magnitude of its charge

  • Physics -

    Well, E = kq/r^2

    E(5)=10
    E(10)=15

    E(5)=10=kQ/(p+.05)^2
    E(10)=15=kQ/(p+.1)^2

    divide the first equation by the second:
    2/3 = [(P+.1)/(P=.05)]^2

    take the sqrt of both sides, solve for P

    Then put P into either equation, solve for Q

  • Physics -

    Since the E-field is pointed along the +x axis at locationa along the x axis, the point charge that causes the field but also be on the x axis. The distance from the point charge to (5,0) must be sqrt (2/3) = 0.8165 times the distance from the point to (10,0), because the field is 2/3 as strong at (5,0) as it is at (10,0).

    The only way you can make this happen is to have the point charge be positive and located to the left x = 0.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. physics

    The electric field at the point and points in the positive direction with a magnitude of 8.00 . At the point and the electric field points in the positive direction with a magnitude of 12.0 . Assume this electric field is produced …
  2. Physics

    3 There are two charges +Q and –Q/2 that locate at two positions with a separation of d as shown in Fig. 1. We may put +Q at the origin of the x-axis to facilitate the calculation. (a) Find the electric field for +Q and –Q/2 at …
  3. physics

    a point charge q1= -4.00nC is at a point (0.6,0.8) in the xy axis, and a second point charge q2=4.73nC is at the point (0.6,0), calculate the magnitude and direction of the net electric field at the origin due to these two points. …
  4. Physics

    The electric field at the point x=5.00 cm and y=0 points in the positive x direction with a magnitude of 10.0 N/C. At the point x=10.0 cm and the electric field points in the positive x direction with a magnitude of 16.0 N/C . Assume …
  5. physics

    The electric field at the point x = 5.00cm and y = 0 points in the positive x direction with a magnitude of 10.0 N/C. At the point x = 10.0cm and y = 0 the electric field points in the positive x direction with a magnitude of 16.0 …
  6. Physics

    There is a very large horizontal conducting plate in the plane (consider it infinitely large). Its thickness is . The charge densities on the upper and the lower surfaces are both equal to . The goal of this problem is to find the …
  7. physics

    Background pertinent to this problem is available in Interactive LearningWare 18.3. A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 5700 N/C and is directed in the positive x direction. …
  8. physics

    A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 5700 N/C and is directed in the positive x direction. A point charge -5.4 × 10-9 C is placed at the origin. Find the magnitude of …
  9. Physics

    A uniform electric field exists everywhere in the x, y plane. This electric field has a magnitude of 5600 N/C and is directed in the positive x direction. A point charge -9.6 × 10-9 C is placed at the origin. Find the magnitude of …
  10. Physics

    A uniform electric field with a magnitude of 6100 V m−1 points in the positive x direction. Find the change in electric potential energy when a +14 μC charge is moved 5 cm in the positive x direction. Answer in joules.

More Similar Questions