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how would i find the integral of sin (2t+1)/cos^2(2t+1) dt

  • math -

    let u = (2t+1)
    du = 2 dt so dt = .5 du
    .5 integral du sin u/cos^2u

    try 1/cos u
    d/du (1/cos u) = -sin u/cos^2 u

    You can take it from there :)

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