# College Physics

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The power dissipated by a light bulb increases by 50 W when the potential difference applied across the light bulb increases from 50 V to 100 V. Find the resistance of the light bulb.

• College Physics -

p=50^2/R
P+50=(100)^2/R
subtract the first equation from the second
50=1/R (100,000-2500)
solve for R. Check my thinking.

• College Physics -

It worked! :D

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