calculus
posted by edwin .
evaluate tan^2 3.658
I know the answer is .322
but I don't know how to arrive at the answer.

I do not think so in either degrees or radians.

Most of us take the calculator and get the answer 0.322398.
The fact that you asked how to get the answer suggests to me that you'd like to do the calculations yourself.
You can do this by expansion of the tan(x) function which involves the evaluation of Bernoulli numbers. If we take advantage of the fact that 1+tan²(x)=sec(x)², or
tan²(x)=sec(x)²1
we only need to evaluate cos(x), which is given algebraically as:
cos(x)=1x²/2!+x^{4}/4!.... 
additional note:
Since tan(x)=tan(x±π), you can calculate tan(xπ) instead of tan(x).
This way, the cosine series converges more rapidly.
Respond to this Question
Similar Questions

Calculus
Evaluate the limit as h > 0 of: [tan (pi/6 + h)  tan(pi/6)]/h I thought the answer was √3/3, or tan(pi/6, but apparently that is wrong, any tips here? 
calculus
Use integration by parts to evaluate the integral of x*sec^2(3x). My answer is ([x*tan(3x)]/3)[ln(sec(3x))/9] but it's incorrect. u=x dv=sec^2(3x)dx du=dx v=(1/3)tan(3x) [xtan(3x)]/3  integral of(1/3)tan(3x)dx  (1/3)[ln(sec(3x))/3] … 
calculus
sin(tan^1(7/3)) How do i evaluate this? 
Trigonometry
Find the exact value of tan(ab) sin a = 4/5, 3pi/2<a<pi; tan b = sqrt2, pi/2<b<pi identity used is: tan(ab)=(tan atan b)/1+tan a tan b simplify answer using radicals. (a is alpha, b is beta) 
calculus
Evaluate h(x) for the following values of x? 
calculus (check my work please)
Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer ∫ sec^3(x)tan^3(x) dx ∫ sec^3(x)tan(x)(sec^2(x)1) dx ∫ tan(x)sec(x)[sec^4(x)sec^2(x)] … 
algebra
Need some one check my homework. Evaluate 3p/q when p=2 and q=6. Answer:1 Use < > or = for __ to write a true sentence: 0.001 __ 0.0010 Answer:< Question 3 Evaluate 3/8  5/8. Answer:7 Question 4 Evaluate: 84 + (99) + 44 … 
Calculus
I tried to integrate this: intergral sign with an interval from inifinity to + infinity function: (xr)^2 (1/r) (e^(x/r)) with respect to dx..... I know that Steve set up the usubstitution but I seem to never arrive at an answer... … 
calculus
Find the exact value of the given expression. (tan17pi/12  tan pi/4) / (1+tan 17pi/12 tan pi/4) can you help with this? 
Calculus Please Check my answer
find d/dx (integral from 2 to x^4) tan(x^2) dx tan(x^4)^2*4x^3 MY ANSWER