Math
posted by Stuck .
How do I solve lim((3x^3  5x +2)/(4x^2 + 3)) as x approaches infinity?
I divided everything by the largest power of x, but I ended up getting a denominator of 0. Do I have to factor this?
(answer is infinity)

You did fine.
When you get c/0, where c is nonzero,
then the limit will approach infinity
It might be easier to see if you divide everything by only x^2.
then lim((3x^3  5x +2)/(4x^2 + 3))
= lim (3x  5/x + 2/x^2)/(4 + 3/x^2)
so as x approaches infinity you are left with 3x/4.
Now as x > ∞ the numerator 3x > ∞
and thus 3x/4 > infinity. 
Oh ok, thank you! My teacher taught us to divide by the largest power of x, so I didn't think of doing it like that.
But I don't quite get how c/0 is infinity. Isn't anything over 0 undefined?