posted by RMZ

how do you solve this
Area of a polygon: A=1/2aP
Perimeter: P=ns

It is a hexagon (6 sides) the sides measure 8cm therefore I have a perimeter measuring
P=6(8)=48 RIGHT?
and for the area I have A=1/2 the apothem= 4 square root of 3 and the P= 48
so, A=1/2(4 square root of 3)48, but how do you solve that??

  1. Reiny

    your answer of
    Area = (1/2)(4√3)(48)
    = 96√3
    should be an acceptable answer, since it is "exact".

    If you want a decimal equivalent, you can use your calculator.

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