okay this is the frst day of grd 11 math and i am doing review and i don't remember anything
what do they mean when they say " determine the velue of the three primary trigonometric ratios for <BAC in each of the following triangle.?
and they give us the length of A-C which is 16cm and B-C which is 24 cm
ps- <ACB is 90 degrees
When you are asked to determine the value of the three primary trigonometric ratios for angle <BAC in a triangle, it means you need to find the values of sine, cosine, and tangent for that angle.
To find these values, you can use the given lengths of the sides of the triangle. In this case, you are given the lengths of A-C and B-C in the triangle. Additionally, it is mentioned that <ACB is 90 degrees, which means that angle BAC is part of a right triangle.
Now, let's find the values of the trigonometric ratios:
1. Sine (sin): Sine is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. In this case, the side opposite angle BAC is A-C, and the hypotenuse is B-C. So, sin(BAC) = A-C/B-C.
2. Cosine (cos): Cosine is defined as the ratio of the length of the adjacent side to the angle to the length of the hypotenuse. In this case, the adjacent side to angle BAC is B-C, and the hypotenuse is B-C. So, cos(BAC) = B-C/B-C.
3. Tangent (tan): Tangent is defined as the ratio of the length of the side opposite the angle to the length of the adjacent side to the angle. In this case, the side opposite angle BAC is A-C, and the side adjacent to angle BAC is B-C. So, tan(BAC) = A-C/B-C.
By substituting the given values of A-C and B-C, you can find the values of sin(BAC), cos(BAC), and tan(BAC).