____Na + ___H2O give us __ NaOH+ ___ H2O
this a chemistry;Balancing Chemical Equation
H2O is water sorry because i don't know how to put 2 in bottom
and explain me how you figuire it out
Your reaction wont balance. the products should be NaOH + H2
To balance the chemical equation Na + H2O → NaOH + H2O, we need to ensure that there is an equal number of each type of atom on both sides of the equation.
Let's break down the equation and count the number of atoms to balance it:
On the left side:
- Sodium (Na) is already balanced; there is 1 Na atom.
- Hydrogen (H) is present in water (H2O), so we have 2 H atoms on the left side.
- Oxygen (O) is also present in water, giving us 1 O atom on the left side.
On the right side:
- Sodium (Na) is already balanced; there is 1 Na atom.
- Hydrogen (H) is present in both sodium hydroxide (NaOH) and water. NaOH has 1 H atom, and water (H2O) has 2 H atoms, totaling 3 H atoms.
- Oxygen (O) is present in both sodium hydroxide (NaOH) and water. NaOH has 1 O atom, and water (H2O) has 1 O atom, totaling 2 O atoms.
To balance the equation, we adjust the coefficients in front of each compound to make the number of atoms equal on both sides.
The balanced equation is:
2Na + 2H2O → 2NaOH + H2O
In this balanced equation, there are:
- 2 Sodium (Na) atoms on both sides.
- 4 Hydrogen (H) atoms on the left side (2 from Na and 2 from H2O) and 4 Hydrogen atoms on the right side (2 from NaOH and 2 from H2O).
- 2 Oxygen (O) atoms on the left side (1 from H2O) and 2 Oxygen atoms on the right side (1 from NaOH and 1 from H2O).
By adjusting the coefficients, we ensure that the equation satisfies the law of conservation of mass, ensuring the same number of each type of atom on both sides.