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Chemistry

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A sample of oxalic acid, H2C2O4, is titrated with standard sodium hydroxide, NaOH, solution. A total of 45.2 mL of 0.12 M NaOH is required to completely neutralize 20.0 mL of the acid. What is the concentration of the acid?


Concentration is Molarity, which is moles solute / liters solution.
Would the L of soln be 45.2 mL + 20.0 mL= 65.2 mL = 0.652 L?

And how do I find the moles solute?

  • Chemistry -

    VolumeAcid*Molarityacid=Volumebase*Molarity base

    VolumeBase=45.1ml
    MolarityBase=.12M
    VolumeAcid=20ml
    Solve for molarity acid.

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