50 mL of 1M silver Nitrate is combined with 25 mL of 2 M potassium Chloride. What is the concentration of a resulting solution
The question makes no sense. What's the concn of what? Ag^+, Cl^-, K^+, or NO3^-. And AgCl is insoluble.
Idk my teacher gave me this question for homework and i had no idea how to do this. But this has to do with molarity and stoichiometrty if that helps
OK. So we give a complete answer.
AgNO3 + KCl ==> AgCl + KNO3
moles AgNO3 initially = L x M = 0.050 x 1 = 0.050 moles.
moles KCl initially = 0.025 x 2 = 0.050 moles.
Since the ratio is 1:1, there are exactly enough moles AgNO3 to react with KNO3. Therefore, moles AgCl formed equals 0.050 moles and the same for KNO3. AgCl is insoluble and KNO3 ionizes completely.
(KNO3) = 0.050 moles/0.100 L = 0.50 M and since it ionizes completely we know (K^+) = 0.5M and (NO3^-) = 0.5M.
AgCl is insoluble, the solution will be saturated with respect to AgCl. Have you gone through how to solve for Ag^+ and Cl^-.
AgCl(s) ==> Ag^+ + Cl^-
If we let solubility AgCl = X, then Ag^+ = X and Cl^- = X
The solubility product = Ksp = (Ag^+)(Cl^-). You can look it up in your text or notes but the number in my text (look up yours for it may very well be different) is 1.1 x 10^-10 so
(X)(X) = 1.1 x 10^-10.
Solve for X and it is 1.05 x 10^-5 M; therefore, the (Ag^+) = (Cl^-) = 1.05 x 10^-5M. You can look up the value in your text and adjust the answer accordingly. This is about as complete an answer as you an get.
To find the concentration of the resulting solution, we can use the concept of the principle of equivalence in a chemical reaction.
First, let's determine the number of moles of silver nitrate and potassium chloride used in the reaction.
Number of moles of silver nitrate = volume (in liters) × concentration
= 50 mL × (1 mol/L)
= 0.05 L × 1 mol/L
= 0.05 mol
Number of moles of potassium chloride = volume (in liters) × concentration
= 25 mL × (2 mol/L)
= 0.025 L × 2 mol/L
= 0.05 mol
Since the reaction takes place in a 1:1 stoichiometric ratio between silver nitrate and potassium chloride, it means that 0.05 moles of silver nitrate would react with 0.05 moles of potassium chloride.
Thus, the resulting solution would contain 0.05 moles of each reactant.
To find the concentration of the resulting solution, we need to know the final volume of the solution. Without this information, we cannot determine the concentration.