posted by mary .
Please help, very lost
Eric has computed that it takes an average (mean) of 17 minutes with a standard deviation of 3 minutes to drive from home, park the car, and walk to his job.
One day it took Eric 21 minutes to get to work. You would use the formula for transforming a raw score in a sample into a z-score to determine how many standard deviations the raw score represents.
Since his "score" is 21, you would subtract the mean of 17 from 21 and divide that result (4) by the standard deviation of 3.
The z-score of 1.33 tells you that Eric’s time to get to work is 1.33 standard deviations from the mean.
Another day, it took Eric only 12 minutes to get to work. Using the same formula, determine the z value. Is it positive or negative? Explain why it should be positive or negative. It is simple what happens when you subtract 21 from 21.
On a different day, it took Eric 17 minutes to get from home to work. What is the z value? Why should you expect this result even before you did the calculation?
First one is right, Z = 1.33.
When you subtract 12 from 21, you get a negative number.
Lastly, Z = 0, since there is no deviation from the mean. It is the mean value.
I hope this helps.