If I have a square and I draw two lines across the middle that interestect what would be the interior angles of that intersection. I know the square itself is 360 degrees and the inner corners are all 45 degrees. I am not sure how to calculate the interior ones.

ex Suppose polygon wxyz is any square with diagonals wy and xz intersecting at point G.
What is the measure of angle xGz?

The two diagonals cross in the middle of the square. All the angles at the intersection are the same. The four of them add up to 360 degrees. 360/4

measure and then draw then draw lines in the rectangle to show it has an area of 36cm

how do i do that?

To find the measure of angle xGz, we can use the fact that the diagonals of a square bisect each other.

Here's how you can calculate it step by step:

1. Start by drawing a square and its diagonals. Label the vertices as w, x, y, and z, and the intersection point of the diagonals as G.

2. Notice that xGz is one of the four smaller triangles formed by the intersecting diagonals. All four triangles are congruent because they share a side (the diagonal) and have a common angle at the vertex (G).

3. Since the sum of the interior angles of a triangle is always 180 degrees, each of these congruent triangles has angle xGz equal to 180 degrees divided by 4.

4. Calculate: 180 degrees ÷ 4 = 45 degrees.

Therefore, the measure of angle xGz is 45 degrees.