Math
posted by Momo .
Solve for the indicated variable:
(x/a)+(y/b)+(z/c) = 1, for c
This is what I have so far:
z/c = 1(x/a)(y/b)
z/c = 1[(xbay)/ab]
z/c=(ab/ab)[(xbay)/ab]
z/c=(abxbay)/ab
...I'm not sure if it's right so far, and if it is, i don't know where to go after that. Help?
Thanks!

Math 
Damon
z/c=(ab/ab)[(xbay)/ab]
z/c=(abxbay)/ab
sign wrong I think
z/c=(abxb+ay)/ab {   is +}
c (abxb+ay) = a b z
c = a b z / (abxb+ay)
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