Hi, I have been asked to simplify the square root of 28 by writing it as a product of an integer and a surd. By practising other calculations I have come up with the answer of 2/7 (sorry couldn't do a square root symbol so have used / instead). I think I may have the right answer but I am still unsure of how it is a product of an integer or a surd, I keep reading up about them both but cannot explain it in my answer. Any help would be very much appreciated, thanks
Yes, the square root is 28 is
sqrt (4*7) = sqrt4 * sqrt7 = 2 sqrt7
I never heard of a "surd"
2 sqrt 7 is your surd
a surd is a numerical expresion containing one or more irrational roots of numbers
its the conventional way of saying
sqrt 7 x 2
Sure! Simplifying the square root of 28 as a product of an integer and a surd means expressing it as the multiplication of a whole number and a number that contains a square root.
To simplify the square root of 28, let's start by finding the largest perfect square that is a factor of 28. In this case, the largest perfect square that divides 28 is 4, since 4 * 7 = 28.
Now, we can express the square root of 28 as the square root of 4 times the square root of 7:
√28 = √(4 * 7)
The square root of 4 is simply 2, so we can substitute that into the expression:
√28 = 2√7
This is the simplified form of the square root of 28 as a product of an integer (2) and a surd (√7).
Therefore, the answer you obtained, 2/7, is not the correct representation of the simplified form. The correct answer is 2√7.