During a particular thunderstorm, the elctric potential difference between the clouds and the groud is Vcloud-Vgroud = 10^9 volts with the cloud being at the higher potential. Now, there is a lightning flash in which a charge of -25C is transferred from the ground to the cloud.

a) how much work is done on the charge by the electric force?

b) if the work done by the elctricforce were instead used to acclerate a 1100kg automobile from rest, what would be its final speed?

c) if the work done were converted to heat, how many kiligrams of water at room temperature could be vaporized?

I know that the heat energy required to vaporize a certain mass of water is Q=cm deltaT + mL. the specific heat capacity of water at room temperature is apporximately c=4186J/(kgxC). The latent heatof vaporization of water is L = 22.6x10^5J/kg. The temperature change is deltaT = (100-20)C

Please help!!!

Nuts to your I know paragraph. This has nothing to do with water heating. It has to do with electrical forces and energy.

Work= Volts*chargetrnasfered
b. 1/2 m v^2= work done by electicity
c. Now use the heat you pointed out.

Electrical work= heat to heat water+ heat to make steam. Solve for the mass water/steam

Sure! I can help you with these questions step by step. Let's start with the first one.

a) To find the work done on the charge by the electric force, we can use the formula:
Work = Electric force x Distance

The electric force is given by the product of charge and the electric potential difference between the clouds and the ground:
Electric force = Charge x Electric potential difference

In this case, the charge transferred from the ground to the cloud is -25C, and the electric potential difference is Vcloud - Vground = 10^9 volts.

So, the electric force = -25C * 10^9 volts.

Now, to find the distance, we need some additional information. If you have the distance or any other information about the setup of the thunderstorm, please provide it so that I can assist you further.

b) To find the final speed of the automobile, we can use the work-energy principle. The work done by the electric force can be equated to the change in kinetic energy of the automobile.

Work done by the electric force = Change in kinetic energy

The work done is already given by the product of the electric force and the distance (which you would need to provide), as calculated in part a.

The change in kinetic energy of the automobile can be calculated using the formula:
Change in kinetic energy = (1/2)mv^2

Where m is the mass of the automobile (given as 1100kg), and v is the final speed we need to find.

Equating the work done to the change in kinetic energy, we can solve for v.

Work done by the electric force = Change in kinetic energy
(Electric force) x (Distance) = (1/2) x (Mass of automobile) x v^2

Substituting the values, you can now calculate the final speed, v.

c) To find the mass of water that can be vaporized when the work done is converted to heat, we need to use the heat formula you provided:
Q = cmΔT + mL

Where Q is the heat energy, c is the specific heat capacity of water (given as 4186J/kgxC), m is the mass of water (which we need to find), ΔT is the temperature change (given as 100-20 = 80C), and L is the latent heat of vaporization of water (given as 22.6x10^5 J/kg).

In this case, the heat energy is equal to the work done by the electric force.

So, we can set up the equation:
Work done by the electric force = cmΔT + mL

Substituting the known values, you can solve for m, which will give you the mass of water that can be vaporized.

Remember to provide the distance (for part a) and any other necessary information to proceed with the calculations.