posted by Bryant .
A resort tracks the number of days each guest stays. They've discovered that this variable is normally distributed with a mean of 9 days and a standard deviation of 3. They would expect 10% of the guest stay longer than how many days?
Please show statistics formula and calcuations using normal probability distribution.
Go to the table I told you about in another post. Find the Z score that corresponds to that 10%. Put the value in the formula below to solve for x.
Z = (x - mean)/standard deviation
I hope this helps.