algebra

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I would like to have some help on this problem please. I'm so post to find the vertex and axis of the parabola.Does anyone have an idea?
Y=x²-16x+63.

A)vertex(8,-1)axis=x=8
B)vertex(8,1)axis=x=8
C)vertex(-8,-1)axis=x=-8
D)vertex(-8,1)axis=x=-8

  • algebra -

    x^2-16x= y-63

    x^2 - 16x + 64 = y+64-63

    (x-8)^2 = y+1

    symmetric about the vertical axis x = 8

    when x = 8, y = -1

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