college physics

posted by .

Let's say that you find a slope of 6.671×10-14 for square plates of width 11.5 cm. What do you get for the value of the permittivity of free space?

  • college physics -

    what slope are you talking about? What is being plotted?

  • college physics -

    Im not really sure, that is all that as being asked.
    Maybe it has to do with this first question as well?.... The electric field near the surface of a uniformly charged conducting plane can be determined by Gauss's law (look it up). If the plane is a square of sides 11.5 cm and carries a charge of 22.0 nC (that's nanocoulombs), what is the magnitude of the electric field near the surface?

  • college physics -

    (-5.00 + 1.00 j)/( 5.00 + 2.00 j )=
    in polar

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. College Physics

    Now we also know that the charge on a pair of parallel plates is proportional to the potential difference V, namely q=CV. We also know that the capacitance of two parallel plates is given by C=ε0A/d, where ε0=8.85×10-12 …
  2. Physics

    A certain parallel capacitor consist of two identical aluminium plates, each of area 2times 10^-4m^2. the plates are separated by a distance of 0,03mm, with air occupying the space between the plates. CALCULATE THE CAPACITANCE OF THE …
  3. physics

    An electron in a computer monitor enters midway between two parallel oppositely charged plates. The initial speed of the electron is 6.15 x 10^7 m/s and its vertical deflection is 4.70 mm. (a) What is the magnitude of the electric …
  4. Physics

    A parallel-plate capacitor is constructed with circular plates of radius 0.056 m. The plates are separated by 0.25 mm, and the space between the plates is filled with dielectric with dielectric constant k. When the charge on the capacitor …
  5. physics

    Two capacitors have the same plate separation, but one has square plates and the other has circular plates. The square plates are a length L on each side, and the diameter of the circular plate is L. The capacitors have the same capacitance …
  6. Physics

    The plates of a parallel-plate capacitor are separated by 0.303 mm. If the material between the plates is air, what plate area is required to provide a ca- pacitance of 3.78 pF ?
  7. Math

    An architect has allocated a rectangular space of 589ft^2 for a square dining room and a 12ft wide kitchen. Find both the width of the square dining room and the length of the entire rectangular space. The width of the square dining …
  8. physics

    Determine the capacitance, in pF, of a paper-filled parallel-plate capacitor (dielectric constant=3.70) having a plate area of 5.40cm2 and plate separation of 590 µm. Use 8.85 x 10-12 F/m for εo, the permittivity of free space
  9. capacitor

    A capacitor is made up of two metal plates, each having an area of 0.02 m2 and spaced 2.5 mm apart. A potential difference of 250 V across the plates establishes a charge of 50 nC. Calculate: a) The electric field strength, b) The …
  10. Physics

    A parallel-plate capacitor is constructed with circular plates of radius 5.6×10−2 m . The plates are separated by 0.27 mm , and the space between the plates is filled with a dielectric with dielectric constant κ. When the …

More Similar Questions