A pole with a height of 60 ft. has a shadow of length of 34.64 ft at a particular instant of time. Find the angle of elevation of the sun at this point of time.
Did you make a diagram?
Which trig ratio uses opposite/adjacent ?
i don't know..i just need help.
To find the angle of elevation of the sun, we can use the relationship between similar triangles formed by the pole, its shadow, and the angle of elevation.
Let's call the angle of elevation of the sun as θ.
Given: Height of the pole = 60 ft, Length of the shadow = 34.64 ft.
In a right-angled triangle, the tangent of an angle is equal to the opposite side divided by the adjacent side.
Therefore, tan(θ) = (opposite side) / (adjacent side).
In this case, the height of the pole is the opposite side and the length of the shadow is the adjacent side.
tan(θ) = 60 ft / 34.64 ft.
To find the angle θ, we need to take the inverse tangent (also known as arctan or tan^(-1)) of both sides.
θ = arctan(60 ft / 34.64 ft).
Calculating this value, we find that θ is approximately 59.06 degrees.
Therefore, the angle of elevation of the sun at this point of time is approximately 59.06 degrees.