math
posted by kim .
Show that some problems have more than one answer by giving at least two answers to the following problem. What change would a restaurant cashier give someone for $1 if he used no more than four of any coin and no coin smaller than a nickel or bigger than a quarter?

Try to come up with 2 combinations of nickels, dimes, and quarters, such that no more than 4 of each are used.
For example: 4 quarters 
There can be no pennies and no dimes, becasue they are smaller than a nickel. Also no Kennedy half dollars. That leaves quarters and nickels to make change with. There could be 0, 1, 2 or 3 nickels and 0, 1, 2 or 3 quarters.
See what change you could make with those combinations. There are a lot more than two possiblities.