what is the name of the amide that is formed by the following reaction:
Butanoic acid + Methylamine?
- CH3CH2CH2COOH + CH3NH2 ---> product + H2O?
i put n-methylbutyramide and they counted it wrong.
N-methylbutanamide
Note the capital N
It is a derivative of butanoic acid so the name will be based on butanamide.
N-methylbutanamide
pentylamide
To determine the correct name of the amide formed by the reaction between butanoic acid and methylamine, it is necessary to consider the structural arrangement of the reactants.
First, let's examine the reactants:
- Butanoic acid has the chemical structure: CH3CH2CH2COOH
- Methylamine has the chemical structure: CH3NH2
When butanoic acid reacts with methylamine, the carboxyl group (-COOH) of butanoic acid reacts with the amino group (-NH2) of methylamine. This reaction leads to the formation of an amide bond, resulting in the final product.
To name the amide, we need to consider the substituents attached to the nitrogen atom. In this case, the substituents are ethyl (CH3CH2CH2-) and methyl (CH3-).
To correctly name the amide, we start by identifying the longest continuous carbon chain. In this case, the longest chain contains four carbon atoms, so it is considered a butyl group. Next, we name the substituents, in alphabetical order, attached to the nitrogen atom. Therefore, the amide formed by this reaction is called N-ethyl-N-methylbutanamide.
Therefore, the correct name for the amide formed by the reaction between butanoic acid and methylamine is N-ethyl-N-methylbutanamide.