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A student claims that the equation the !-x = 3 (square root of) has no solution, since the square root of a negative number does not exist. Why is this argument wrong? (The teacher does not want us to work the problem out, only tell why it is wrong.)

  • math -

    If you mean
    sqrt(-x) = 3
    then as long as x is negative, you are taking the square root of a positive number.

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