math
posted by brenda .
A student claims that the equation the !x = 3 (square root of) has no solution, since the square root of a negative number does not exist. Why is this argument wrong? (The teacher does not want us to work the problem out, only tell why it is wrong.)

If you mean
sqrt(x) = 3
then as long as x is negative, you are taking the square root of a positive number.