can you show how u got the ansr on this question?
a small pebble is heated and placed in a foam cup calorimeter containing 25.0mL of water at 25 degrees celsius. the water reaches a maximum temp of 26.4 degrees celsius. how many joules of heat were released by the pebble?
again... please show me how u got the answer.
q = mass x specific heat x delta T.
mass = 50 g
specific heat = 4.184 J/g*C
delta T = 26.4 - 25.0
Check my numbers.