i know that the slop intercept form is

y-y1=m(x-x1)
i have to write an equation for a line that has a slope of 6 and contains the point (-8,-7) even with the formula i don't now how, HELP!!!!

Sure! I can help you out. To write an equation for a line with a slope of 6 and contains the point (-8, -7), you can use the slope-intercept form of a linear equation, which is:

y = mx + b

Here, "m" represents the slope of the line, and "b" represents the y-intercept. So, we need to find the value of "b" given the slope and the point on the line.

To find the value of "b", we can substitute the coordinates of the given point (-8, -7) into the equation. So, we have:

-7 = 6(-8) + b

Now, we can simplify and solve for "b". Multiplying 6 with -8 gives us -48:

-7 = -48 + b

To solve for "b", we need to isolate it on one side of the equation. We can do this by adding 48 to both sides:

-7 + 48 = b

Simplifying, we get:

41 = b

Now that we have the value of "b", we can substitute it back into the slope-intercept form equation:

y = 6x + 41

Therefore, the equation for the line with a slope of 6 and containing the point (-8, -7) is y = 6x + 41.