When given sin(5x)=0, and asked to find x, I would basically have to solve for 5x first, and then divide my answers by 5.
My question is if it was, for example, sin(5x+2)=0, would I minus 2, then divide by 5? Or divide by 5 then minus 2?
You don't specify if you want your x to be in degrees or radians.
I will assume it is radians
So
sin(5x+2) = 0
then
1. 5x+2 = 0
or
2. 5x + 2 = pi
or
3. 5x + 2 = 2pi etc
1. 5x+2 = 0
5x = -2
x = -2/5 radians
2. 5x+2 = pi
5x = (pi - 2)
x = (pi - 2)/5 radians
etc.
Thank you!
Oh, sorry! I assumed it wouldn't have an effect on my question.
To solve the equation sin(5x + 2) = 0, you can begin by subtracting 2 from both sides of the equation:
sin(5x + 2) - 2 = 0 - 2
sin(5x + 2) = -2
Now, it's important to note that the sine function only takes values between -1 and 1. Since -2 is outside this range, there are no solutions for this equation.
In general, when you have an equation of the form sin(ax + b) = 0, where a and b are constants, you would need to solve for ax + b first, and then isolate x by dividing by a. However, in this specific example, there are no solutions as the value of -2 is outside the range of the sine function.
To solve the equation sin(5x+2)=0, you need to isolate the variable x. Here's the step-by-step process:
1. Subtract 2 from both sides of the equation: sin(5x+2) - 2 = 0.
2. Now, we have sin(5x) = -2.
3. Since the range of the sine function is -1 to 1, there are no real solutions for sin(5x) = -2. Therefore, this equation has no real solutions.
In general, when dealing with trigonometric equations, you typically manipulate the equation to isolate the trigonometric term on one side and the constant value on the other side. Then, you attempt to solve for the angle or variable within the domain of the trigonometric function.
So, specifically in this case, you would subtract 2 from both sides first, then try to solve for 5x. However, be aware that in this particular example, there are no real solutions for the equation sin(5x+2)=0.