posted by Michelle .
The areas of the faces of a rectangle box are 48 m2, 96 m2, and 288 m2. A second box is cubical and each of its faces has area 16m2. Find the ratio of the volume of the first box to the volume of the second box.
how about letting the 3 lengths of the first cube be a, b, and c
ab = 288
ac = 96
bc = 48
from that you could do stuff like
ab/(ac) = 288/96
b/c = 3
b = 3c
using other variations, and subbing back, I found
a = 24
b = 12
c = 4 (the side areas check out)
so the volume of the first is .....
I am sure you can finish it.