physics
posted by Sarah N H .
Sam is sitting in her fishing boat watching a trout swim below the surface. She guesses the apparent depth of the trout at 2.0m. She estimates that her eyes are about 1.0 m above the water's surface, and that the angle at which she's observing the trout is 45 degrees.
b) Calculate the actual depth of the trout
I have calcualted the angle of incidence to be 32 degrees, but still have no idea how to figure out the depth. I have been trying for 2 hours since last night. I don't know what trig to use on this. Can you help please?

http://www.saburchill.com/physics/chapters3/0004.html
So Real depth= apparent depth/ tan i
check my thinking. 
The formula that you need is derived and presented here:
http://www.physicstutorials.org/index.php/home/optics/refractionoflight/apparentdepthrealdepth
The object will appear at a shallower depth equal to the real depth divided by the refractive index of water. 
Bob: your website, when I rearrange the formula, would be real depth = X/tani...What is the 'x" in my problem?
DRWLS: I am solving for the actual depth, the apparent depth is given...do I still use your same formula?
Thankyou both.
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