physics  power(3)
posted by Mota .
A force of 48 N pushes a 2 kg object initially at rest a distance of 3m along frictionless horizontally surface. Find:
A The work done on the object.
B The power of the applied force.

work=force*distance
Vf^2=2 a *d= 2 (48/2)*3
or Vf=12 m/s
avg velocity= 6m/s
power= force*d/time=force*avg velocity