physics
posted by Mary .
A golfer rides in a golf cart at an average speed of 3.10 m/s for 26.0 s. She then gets out of the cart and starts walking at an average speed of 1.20 m/s. For how long (in seconds) must she walk if her average speed for the entire trip, riding and walking, is 2.30 m/s?

avg speed= total distance /time=(ride distance + walk distance*timewalking)/(26s+timewalking)

The Kentucky Derby is held at the Churchill Downs track in Louisville, Kentucky. The track is one and onequarter miles in length. One of the most famous horses to win this event was Secretariat. In 1973 he set a Derby record that would be hard to beat. His average acceleration during the last four quartermiles of the race was +0.0105 m/s2. His velocity at the start of the final mile (x = +1609 m) was about 16.58 m/s. The acceleration, although small, was very important to his victory. To assess its effect, determine the difference between the time he would have taken to run the final mile at a constant velocity of +16.58 m/s and the time he actually took. Although the track is oval in shape, assume it is straight for the purpose of this problem.
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