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chemistry

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The Rydberg equation (1/lambda=R/ni^2–R/nf^2) can be treated as a line equation. What is the value of nf as a function of the slope (m) and y-intercept(b)?

by GC 1/lambda = R/ni^2–R/nf^2
y = mx + b (standard form) of a linear equation)
x = (y-b)/m
Let,
y = 1/lambda
m = -R
x = 1/nf^2
b = R/ni^2
1/nf^2 = [(1/lamda)-(R/ni^2)]/(-R)
Solve for nf
i still don't get how you get rid of y and x to get m and b in the end

  • chemistry -

    Answer is (m/b)^1/2

  • chemistry -

    I don't know the answer to this question but I put the answer given above is wrong if you are doing the uci webwork from chem 1LB

  • Chem1LB -

    dude its (-M/B)^(1/2)

  • chemistry -

    im doing uci webwork and that's right
    (-M/B)^(1/2)

  • chemistry -

    Alex Le and bowisha
    you're all probably stupid in school
    thats y u want to let people down idiots
    answer is correct as mb to the 1/2
    not negative
    this is the Right answer

  • chemistry -

    I'm doing the webwork for uci, not sure what the answer is but it's not (m/b)^-1/2. thanks people....

  • chemistry -

    it's negative

  • chemistry -

    yo it is (-m/b)^(1/2) i just did it and submitted.

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