posted by Joe .
I do not understand how to do this problem
((sin^3 A + cos^3 A)/(sin A + cos A) ) = 1 - sin A cos A
note that all the trig terms are closed right after there A's
sin A cos A
sin (A) cos (A)
I wrote it out like this
0 = - sin^6 A - cos^6 A + 2sin^3 A cos^3 A - 2sin^3 A - 3sin^2 A cos^2 A - 2sinA cosA + 1
I graphed the problem and my solution and got the same line so my questio is how do i simplify thank you????