math
posted by Breauna .
Write the standard equation for the parabola with the given characteristics.
vertex:(0,0)
directrix:y= 1.

The equation x^2 = 4 py is a parabola with vertex at (0,0) and a directrix below it at y = p. You want p to be 1.
Therefore 4p = 1 and p = 1/4
y = x^2 /4 is the equation
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