how many grams of CaCl2 would be dissolved in 1.9 liters of a 0.2 molarity solution of CaCl2?
molarity = moles/L
You have L and you have M, calculate moles.
Then moles = g/molar mass. You have molar mass and moles (from above), calculate g.
To find the number of grams of CaCl2 dissolved in 1.9 liters of a 0.2 molarity solution of CaCl2, you'll need to consider the formula of CaCl2 and use some conversion factors.
The formula weight of CaCl2 is 110.98 g/mol. This means that one mole of CaCl2 weighs 110.98 grams.
First, you need to find the number of moles of CaCl2 present in 1.9 liters of the solution. To do this, use the formula:
moles = molarity x volume
Where:
molarity = 0.2 M (0.2 moles per liter)
volume = 1.9 liters
Substituting the values into the formula, we get:
moles = 0.2 M x 1.9 L = 0.38 moles
Now, convert moles of CaCl2 to grams using the formula weight:
grams = moles x formula weight
grams = 0.38 moles x 110.98 g/mol = 42.18 grams
Therefore, approximately 42.18 grams of CaCl2 would be dissolved in 1.9 liters of a 0.2 molarity solution of CaCl2.