A reporter covering a naturalization ceremony wants to randomly select new citizens to interview. Out of the 200 new American citizens, 7 of them are from Ecuador, and 10 of them are from Kenya. What is the probability that the reporter will randomly select a person from Ecuador first and then a person from Kenya to interview?
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7/200 for the Ecuadorian, 10/199 for the Kenyan (one non-Kenyan person is already gone).
The probability of both (or all) events is found by multiplying the probabilities of the individual events.
I hope this helps.
The answer is 7/3,980. By the way, this is 6th grade, not 9th!
@bella / its on a high school test to see what level youre performing at, it asks you a bunch of math questions from many grades
To calculate the probability of selecting a person from Ecuador first and then a person from Kenya, we can use the concept of conditional probability.
Step 1: Find the probability of selecting a person from Ecuador first.
Out of the 200 new American citizens, there are 7 from Ecuador. So, the probability of selecting a person from Ecuador first is 7/200.
Step 2: Find the probability of selecting a person from Kenya second, given that a person from Ecuador has already been selected.
After selecting a person from Ecuador, there are now 6 remaining Ecuadorian citizens, and out of the remaining citizen pool, there are 10 citizens from Kenya. So, the probability of selecting a person from Kenya second, given that a person from Ecuador has already been selected, is 10/199.
Step 3: Multiply the probabilities from Step 1 and Step 2 to find the desired probability.
The probability of two independent events occurring in sequence is obtained by multiplying their individual probabilities. Therefore, the probability of selecting a person from Ecuador first and then a person from Kenya is (7/200) * (10/199).
Calculating this expression gives a probability of approximately 0.001767 or about 0.18%.