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How is magnesium formed (detailed answer)

Here are some notes on a non-commercial method. Commercial methods are different.

http://www.ivstandards.com/tech/samprep/part04.asp

Similar Questions

if a mass of 2.4 g of magnesium is burnt in air, 4.0g of magnesium oxide is formed.1- what kind of reaction is this ? explain

Top answer: 1) 2.30 2)2.30 Read more.
A 3.214-g sample of magnesium reacts with 8.416g of bromine. The only product is magnesium bromide. If 1.934g of magnesium is

Top answer: Write the equation and balance it. Mg + Br2 ==> MgBr2 Convert 3.214 g Mg to moles. moles = Read more.
A piece of magnesium weighing 48 grams is burned in air n 80 gram of magnesium oxide is formed. what mass of oxygen combined

Top answer: looks like 32 g of O2, no? Read more.
A piece of magnesium ribbon weighting 50g is burn in air and 80g of magnesium oxide is formed. What mass of oxygen combined with

Top answer: The law of conservation of mass tells you that mass is neither created nor destroyed. 2Mg + O2 ==> Read more.
A piece of magnesium ribbon weight 24g is burn in air an 40g magnesium oxide is formed. What mass of oxygen combined with the

Top answer: 24 g of Mg is how many mols of Mg ? so How many mols of O ? (Hint: MgO has exactly as many mols of O Read more.
thanks for the responses but i still don't understand it.I think its more detailed what i have to find now. I have to find the

Top answer: well if magnesium sulfide is MgS can you figure it out now? Read more.
The following is a Limiting Reactant problem:Magnesium nitride is formed in the reaction of magnesium metal with nitrogen gas in

Top answer: There are shorter ways to do this but they are harder to explain. I do them the long way this way. Read more.
The following is a Limiting Reactant problem: Magnesium nitride is formed in the reaction of magnesium metal with nitrogen gas

Top answer: Do you have any choices or is it one where you answer it with what you know? Read more.
Magnesium nitride is formed in the reaction of magnesium metal with nitrogen gas in this reaction: 3 Mg(s) + N2(g) --> Mg3N2(s)H

Top answer: First thing first: write and balance the euqation. In this case, it is already balance. Next, given Read more.
Assuming an efficiency of 30.80%, calculate the actual yield of magnesium nitrate formed from 147.4 g of magnesium and excess

Top answer: Mg + Cu(NO3)2 ==>Mg(NO3)2 + Cu mols Mg = 147.4/atomic mass Mg = ? mols Cu(NO3)2 formed = mols Mg Read more.